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    can anybody help..... - Posted on 2007-03-13 19:07:24

bazzoka
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can anybody help me with this math problem...... x= 3+ln[y/1-y]........now im trying to make y the subject. so far ive gotto e^x-3= y/1-y the bit im struggling with is how to get y the subject or even y^2, so that i can complete the equation....any help here would be greatly appreciated. Ta.

 

 

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   can anybody help..... - Posted on 2007-03-13 19:40:27

catherine
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working on it, give me five mins, but where did you get 'e' from?????

 

   can anybody help..... - Posted on 2007-03-13 19:44:47

bazzoka
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e is the base to ln, the naperian log, basically is the oppostie so that i could get y/1-y on its own?...or did i really bend the rules for that one?lol

 

   can anybody help..... - Posted on 2007-03-13 19:47:52

catherine
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Sorry, I'm really rusty on this, but would it not be: x/3+ln+y/1-y

 

   can anybody help..... - Posted on 2007-03-13 19:48:55

catherine
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Either way, still thinking how to get y as the subject!!!

 

   can anybody help..... - Posted on 2007-03-13 19:50:14

catherine
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Bugger, should have been = where I put the second +

 

   can anybody help..... - Posted on 2007-03-13 19:50:48

bazzoka
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lol, no it aint the original equation is x = 3+ ln(y/1-y), lol thats what i got to transpose it across unl;ess i got it wrong..lol....has got me stumped even my other brain at work!lol, mainly gettin y the subject!!lol

 

   can anybody help..... - Posted on 2007-03-13 19:52:07

bazzoka
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i see what you mean but i was changing back to an index form from a log from, if ya get me there? followingf the laws of logs.

 

   can anybody help..... - Posted on 2007-03-13 19:53:26

catherine
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Over my head, never did logs lol

 

   can anybody help..... - Posted on 2007-03-13 19:54:07

bazzoka
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lol...i did but still dont ghet it! but sshhhhh..lol, still cant quite get y as the subject though!lol..

 

   can anybody help..... - Posted on 2007-03-13 20:00:55

catherine
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Nope, nor me!!!! If I were you, I would do as I did at Uni, and that is cheat!!!! Have you not got a uni/college/work mate that can help out? Sorry, just tooooooo long since I did this stuff lol

 

   can anybody help..... - Posted on 2007-03-13 20:28:48

Speedofile
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This is too difficult..looks like greek!!

 

   can anybody help..... - Posted on 2007-03-13 20:30:23

vfor
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Y= (3-IN) --------- X

 

   can anybody help..... - Posted on 2007-03-13 20:33:30

Speedofile
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I feel really stupid now!!

 

   can anybody help..... - Posted on 2007-03-13 20:33:08

vfor
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( 3-IN) Y = ----------- X

 

   can anybody help..... - Posted on 2007-03-13 20:35:13

Speedofile
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3 inches?

 

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